Tuesday 9 August 2011

T/T/S Time Table

10:10 - 11:40 ---> Electric Field
11:50 - 13:20 ---> Vectors
15:10 - 16:40 ---> Equilibrium of Forces
18:30 - 20:00 ---> Capacitors

Wednesday 13 July 2011

Topics to be taught in the first lecture on Coulomb's Law

1)        Quantisation of Charge
2)        Properties of force between two point charges
3)        Coulomb’s Law for point charges
4)        Value of Coulomb’s constant
5)        Permittivity of free space
6)        Relative permittivity and Dielectric Constant
7)        Force between two charges in another medium
8)        Place where a third charge experiences no force due to two              
     charges.
9)        Principle of Superposition of Forces.
10)       Coulomb’s Law in Vector Form.

Topics to be taught in the first lecture on Gauss Law

1)       Concept of Area as a vector
2)       Plane Area as a vector
3)       Irregular Area as a vector
4)       Number of electric lines of force and flux
5)       Positive and negative flux
6)       Formula to calculate electric flux through any plane surface
7)       Formula to calculate electric flux through any curved surface
8)       To calculate flux due to constant Electric Field
9)       To calculate flux due to variable magnetic field
10)       Gauss law and flux
11)       Properties of the electric field calculated due to gauss law.
12)       Properties of the charge appearing in gauss law.
13)       Proof of Gauss Law and tips for choosing Gaussian surface.

Topics to be taught in the first lecture on Newton's Law of Motion

1)  Newton’s first law of motion.
2)  Newton’s second law of motion.
3)  Way to solve simple problems of blocks.
4)  Blocks connected with a string and kept on a horizontal surface.
5)  Blocks connected with a string and moving vertically upwards.
6)  Block kept on an inclined plane
7)  Blocks connected with a string and moving on an inclined plane.
8)  Blocks kept on a double inclined plane and connected with a string.
9)  Constraints
a.     Constraints for strings.
b.    Constraints for objects in contact with each other.

Monday 6 June 2011

Kinematics(Motion in a straight line with constant acceleration)(Problems)


1). A car travels the first half of a distance between two places at a speed of 30km/hr and second half of the distance at 50 km/hr. Find average speed of the car for the whole journey.

2). A motor car moving with a uniform speed of 20 m/s comes to a stop on the application of brakes after travelling a distance of 10 m. Find the acceleration of the car.

3). A body travels for 15 sec starting from rest with constant acceleration. If it travels distances S1, S2 and S3 in the first 5 seconds, second 5 seconds and the third 5 seconds respectively, then find S1:S2:S3.
4). The relation 3t=sqrt(3x) + 6 describes the displacement of a particle in one direction. Find the displacement of the particle when its velocity is zero.

5). A particle is moving eastwards with velocity of 5 m/s. In 10 sec, the velocity changes to 5 m/s northwards. Find the average acceleration.

Kinematics(Motion in a straight line with constant acceleration)(Problems)

1). The position of a particle along the x-axis is given by 9.75+1.5t3. Find:
(          a)    Average velocity between t=2 and t=3 seconds.
           b)   Instantaneous velocity at t=2 seconds.
           c)    Instantaneous velocity at t=2.5 seconds.

2). A motorcyclist moving with uniform retardation takes 10 sec and 20 sec respectively to travel
     successive quarter km. How much further will he travel before coming to rest?
3). A point moving in a straight line traversed half the distance with a velocity v0. The remaining part of the
     distance was covered with velocity v1 for half the time, and with velocity v2 for the other half of the
     time. Find the mean velocity of the point averaged over the whole time of motion.
4).At the instant a traffic light turns green, a car starts with a constant acceleration of 2.2 m/s2. At the same
    instant a truck, travelling with a constant speed of 9.5 m/s2 overtakes and passes the car.
    (a) How far beyond the starting point will the car overtake the truck?
    (b) How fast will the car be travelling at the instant?
5).A train is crossing an observer standing on a platform. The first compartment of the train takes 2 sec to
    cross the observer while the second compartment of the train takes 2.5 sec to cross him. The train is
    moving with uniform acceleration. Find
    (a) Velocity of the train when the front of the first compartment crosses the observer.
    (b) The acceleration of the train
    (The length of each compartment is 15 m.)

Wednesday 1 June 2011

Kinematics(Basic Definitions)(Numericals 6 to 9)

6).  A particle moves in a circle of radius R=21/22 m with constant speed 1 m/s. Find:
     (a) Magnitude of average velocity in 2 seconds
     (b) Magnitude of average acceleration in 2 seconds

7).  A particle is moving in x-y plane. At time t=0, particle is at (1,2) and has velocity 4i+6j. At t=4, particle reaches (6,4) and has velocity 2i+10j. In the given time interval, find,
     (a) Average velocity
     (b) Average Acceleration

8).  A particle is moving in a circle of radius 4 cm with constant speed of 1cm/s. Find:
     (a) Time period of the particle
     (b) Average speed of the particle in time t=0 to t=1 sec.
     (c) Average velocity of the particle in time t=0 to t=1 sec.
     (d) Average acceleration of the particle in time t=0 to t=1 sec.

9). A particle moves in a straight line with a constant speed of 4m/s for 2seconds, then with 6 m/s for 3 seconds. Find the average speed of the particle in the given time interval.

Kinematics(Basic Definitions)(Numericals 1 to 5)

1). A farmer has to go to 500 m due north, 400 m due east and 200 m due south to reach his field. If he takes 20 minutes to reach the field:
     (a)  Find distance
     (b)  Find displacement
     (c)  Find average speed
     (d)  Find average velocity

2). The length of a seconds hand in watch is 1 cm. Find the change in the velocity of its tip in 15 seconds.

3). A particle moving along a straight line travels half of a distance with uniform speed 30 m/s and the remaining half of the distance with speed 60 m/s. Find the average speed of the particle.

4). A car moves with 60 km/hr in the first 1 hour and with 80 km/hr in the next half and hour. Find:
     (a).  total distance travelled by the car.
     (b).  average speed of the car in total 1.5 hours

5). A block moves in a straight line with velocity v for time t. Then its velocity become 2v for next time interval t. Finally its velocity becomes 3v for time T. If average velocity during the complete journey was 2.5v, then find T in terms of t. 

Kinematics(Basic Definitions)(Theory Portion)

Theory Portion:
1).  Position Vector
2).  Displacement Vector
3).  Distance
4).  Average Velocity
5).  Average Speed
6).  Instantaneous Speed
7).  Instantaneous Velocity
8).  Average Acceleration
9).  Instantaneous Acceleration

Thursday 31 March 2011

Monday 21 March 2011

So Many IITs, and you need only one seat to make your life wonderful.

The total number of IITs as of now:


1).IIT Kharagpur
2).IIT Mumbai
3).IIT Chennai
4).IIT Kanpur
5).IIT Delhi
6).IIT Guwahati
7).IIT Roorkee
8).IIT Bhubaneswar
9).IIT Gandhinagar
10).IIT Hyderabad
11).IIT Patna
12).IIT Punjab
13).IIT Rajasthan
14).IIT Indore
15).IIT Himachal Pradesh


Only one seat required to change your life.



Saturday 19 March 2011

1st Question of Kinematics from I.E.Irodov - must for anyone who starts IIT JEE preparation

Q)    A motorboat going downstream overcame a raft at a point A. T= 60 minutes later it turned back and after some time passes a raft at a distance l = 6 km from the point A. Find the flow velocity assuming the duty of the engine to be constant.

Ans.

Let the velocity of the stream = u km/hr
Let the velocity of the motorboat with respect to the stream = v km/hr
Then,
The velocity of the motorboat downstream = v+u km/hr
The velocity of the motorboat upstream = v-u km/hr

The  speed of the raft = speed of the stream = u.

The distance mved by the raft till the motorboat turns back = u(1) km
The distance moved by the motorboat in 1 hour = (u+v )1 km

 The motorboat reaches the turning point in 1 hour. By this time the raft has moved a distance "u" km. Now, the motorboat turns back and moves some distance to meet the raft which is still moving with a speed u.
Time take by the raft to cover the rest of the distance =  (6-u)/u hours.
The distance moved  by the motorboat in this time = (v-u)(6-u)/u km.
So we can say that,
The distance moved by the motorboat to reach the turning point =  Distance between A and the starting point + Distance between the turning point of  the motorboat and the meeting point of the motorboat and the raft. 

Thus,

6 + (v-u)(6-u)/u  =  v+u
This when solved gives us
u = 3 km/hr!!!
Have Fun Guys!!!


For any doubts, drop an email on rajat.etoos@gmail.com.

    


Friday 18 March 2011

Answers

The answer to this question will be posted in the subsequent blog

Thursday 17 March 2011

First Question

Q.         One mole of an ideal monoatomic gas is taken round the cyclic process ABCA as shown in figure. Calculate.
            (A) the work done by the gas.                        
            (B) the heat rejected by the gas in the path CA and heat absorbed in the path AB.
            (C) the heat absorbed by the gas in the path BC.
             (D) the maximum temperature attained by the gas during the cycle.

For any Doubts

For any doubts on the topics in physics, please mail to me at rajat.etoos@gmail.com

Wednesday 16 March 2011

Starting of The Physics blog

From now on, I will be posting many questions of IIT JEE Physics on this blog. You can solve them. The next day I will be giving the answers and the solutions.