First Law of Thermodynamics

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Questions(Different Thermodynamic Processes)

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Questions on Capacitance

Kinematics

Questions on Rotational Mechanics

So Many IITs, and you need only one seat to make your life wonderful.

The total number of IITs as of now:


1).IIT Kharagpur
2).IIT Mumbai
3).IIT Chennai
4).IIT Kanpur
5).IIT Delhi
6).IIT Guwahati
7).IIT Roorkee
8).IIT Bhubaneswar
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Only one seat required to change your life.

1st Question of Kinematics from I.E.Irodov - must for anyone who starts IIT JEE preparation

Q)    A motorboat going downstream overcame a raft at a point A. T= 60 minutes later it turned back and after some time passes a raft at a distance l = 6 km from the point A. Find the flow velocity assuming the duty of the engine to be constant.

Ans.

Let the velocity of the stream = u km/hr

Let the velocity of the motorboat with respect to the stream = v km/hr

Then,

The velocity of the motorboat downstream = v+u km/hr

The velocity of the motorboat upstream = v-u km/hr

The  speed of the raft = speed of the stream = u.

The distance mved by the raft till the motorboat turns back = u(1) km

The distance moved by the motorboat in 1 hour = (u+v )1 km

 The motorboat reaches the turning point in 1 hour. By this time the raft has moved a distance "u" km. Now, the motorboat turns back and moves some distance to meet the raft which is still moving with a speed u.

Time take by the raft to cover the rest of the distance =  (6-u)/u hours.

The distance moved  by the motorboat in this time = (v-u)(6-u)/u km.

So we can say that,

The distance moved by the motorboat to reach the turning point =  Distance between A and the starting point + Distance between the turning point of  the motorboat and the meeting point of the motorboat and the raft. 

Thus,

6 + (v-u)(6-u)/u  =  v+u

This when solved gives us

u = 3 km/hr!!!

Have Fun Guys!!!

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Answers

The answer to this question will be posted in the subsequent blog

First Question

Q.         One mole of an ideal monoatomic gas is taken round the cyclic process ABCA as shown in figure. Calculate.

            (A) the work done by the gas.                        

            (B) the heat rejected by the gas in the path CA and heat absorbed in the path AB.

            (C) the heat absorbed by the gas in the path BC.

             (D) the maximum temperature attained by the gas during the cycle.

For any Doubts

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Starting of The Physics blog

From now on, I will be posting many questions of IIT JEE Physics on this blog. You can solve them. The next day I will be giving the answers and the solutions.